Let be a graph with at least half of the vertices having degree at least . For a tree with edges, Loebl, Komlós, and Sós conjectured that contains . It is known that if the length of a longest path in (i.e., the diameter of ) is at most 5, then contains . Since is a bipartite graph, let be the number of vertices in the smaller (or equal) part. Clearly . In our main theorem, we prove that if , then the graph contains . Notice that this includes certain trees of diameter up to .
If a tree consists of only a path and vertices that are connected to the path by an edge, then the tree is a caterpillar. Let be the path obtained from the caterpillar by removing each leaf of , where . The path is the spine of the caterpillar , and each vertex on the spine of with degree at least 3 in is a joint. It is known that the graph contains certain caterpillars having at most two joints. If only odd-indexed vertices on the spine are joints, then the caterpillar is an odd caterpillar. If the spine has at most vertices, then is a short caterpillar. We prove that the graph contains every short, odd caterpillar with edges.