Combinatorial Bounds of the Regularity of Elimination Ideals

Muhammad Junaid Ali Junjua1, Khurram Shabbir1, Asim Naseem1
1Govt. College University, Lahore, Pakistan.

Abstract

Elimination ideals are monomial ideals associated to simple graphs, not necessarily square–free, was introduced by Anwar and Khalid. These ideals are Borel type. In this paper, we obtain sharp combinatorial upper bounds of the Castelnuovo–Mumford regularity of elimination ideals corresponding to certain family of graphs.

Keywords: Primary decomposition, Castelnuovo–Mumford regularity, Stable ideal, Strongly stable ideals

1. Introduction

Let S=k[x1,,xn] be a polynomial ring in n–variables over an infinite field k. We say that a monomial ideal IS is of Borel type, see [1], if it satisfies the following condition: (I:xj)=(I:(x1,,xj)) for all 1jn. The Castelnuovo–Mumford regularity of I is the number reg(I)=max{ji|βij(I)0}, where βij(I) are the graded Betti numbers of I. The regularity of monomial ideals of Borel type is extensively studied, see for instance [2,3,4,5].

Let G be a simple connected graph on the vertex–set V(G)={x1,,xn} and edge–set E(G). There are a number of ways to study the algebraic properties of the graph by associating a monomial ideal to it, well known among all are edge–ideals. Recently, Anwar and Khalid in [3] introduced a new class of monomial ideals, namely; elimination ideals ID(G), associated to G. They showed that the elimination ideals are monomial ideals of Borel type. They gave the description of Graphical Degree Stability of graph G denoted by Stabd(G); a combinatorial measure associated to G. They gave a systematic procedure to compute the graphical degree stability, namely Dominating Vertex Elimination Method (DVE method). They computed the upper bound of the Castelnuovo–Mumford regularity of elimination ideals for complete graph, star graph, line graph, cyclic graph, fan graph, friendship graph and wheel graph.
Motivated from [3], we further extended this study to other family of graphs. We succeeded to obtain a sharp combinatorial bound for the Castelnuovo–Mumford regularity of elimination ideals associated to regular Harary graphs Hn2,n (see theorem 3). We obtain similar result for the join of complete graph and Path Graph; KnPm (see theorem 3) and for complete bipartite graph; Km,n (see theorem 4)

2. Background

Throughout in this paper, we consider G as a finite simple connected graph with vertex set V(G)={x1,,xn} and S=k[x1,,xn] be the associated polynomial ring over an infinite field k, also the edge set of G will be denoted by E(G). As |V(G)| is finite, we may use the set [n]={1,2,,n} instead of V(G) and we shall always use [n] to label the vertices in figures.
Let xiV(G), then the number of edges incident to xi is called the degree of xi and is denoted by deg(xi), if deg(xi)deg(xj) for all xjV(G), then xi is called dominating vertex of G, and the set of all dominating vertices of G is called the dominating set of G, denoted as D(G). A vertex xiV(G) with deg(xi)=0 is called an isolated vertex of G. We call G a scattered graph, if it has at least one isolated vertex, otherwise, non-scattered graph. A finite sequence of nonnegative integers is called graphical degree sequence if it is a degree sequence of some graph. Throughout in this paper, we assume that deg(x1)deg(x2)deg(xn) in G. Now, we recall important definitions from [3].

Definition 1. Let Gi be a graph and pick a vertex x in D(Gi) such that Gi+1:=Gi{x} is an induced, non-scattered subgraph of Gi. This method of obtaining an induced, non-scattered subgraph Gi+1 from Gi by eliminating a vertex from the dominating set D(Gi) is called the dominating vertex elimination method, the method is known as DVE method. See  [3] for more details.

Let G:=G0 be a graph with vertex set [n], then the length of the maximum chain of induced, non scattered subgraphs of G obtained by successively using DVE method is called the graphical degree stability of G, and it is formally denoted by Stabd(G). In other words, if G:=G0G1Gk is the maximum chain of induced, non scattered subgraphs of G then Stabd(G)=k. Note that Gk is a subgraph of G with vertex set [nk].

Definition 2. Let Gi be a graph with vertex set V(Gi)={x1,x2,,xi} and having the degree sequence (d1,d2,,di), then the ideal Qi:=x1d1,x2d2,,xidi is called the sequential ideal of Gi. Let G:=G0G1Gk be the maximum chain of induced, non scattered subgraphs of G obtained by DVE method with Stabd(G)=k, then ID(G):=j=0kQj is called the elimination ideal of G.

Now, we recall some definitions from graph theory.

Definition 3. Let G and H be two graphs with mutually disjoint vertex sets V(G)={u1,u2,un} and V(H)={w1,w2,,wm}. A graph, denoted by GH, is called the join of G and H if V(GH)=V(G)V(H) and E(GH)=E(G)E(H){uiwj|uiV(G), wjV(H)}.

Definition 4. Let G be a graph with vertex set V(G). A subset X of V(G) is called an independent set if no two vertices of X are adjacent. A k-partite graph is a graph whose vertex set V(G) can be partitioned into k distinct independent sets. A complete k-partite graph is a k-partite graph with every two vertices from distinct independent sets are adjacent. If k=2, then graph is bipartite.

We conclude this section by recalling some important definitions and results regarding stable properties of ideals.
Let IS=k[x1,,xn] be a monomial ideal. For any monomial uS set m(u):=max{j| xj|u} and m(I)=max{m(u)| uG(I)}, where G(I) denotes the set of minimal monomial generators of I. The highest degree of monomial in G(I) is denoted by deg(I). Also, It is the monomial ideal generated by monomials of I of degree t. A monomial ideal I is stable if for each monomial uI we have xj.uxm(u)I for all 1j<m(u). We set q(I)=m(I)(deg(I)1)+1.
Eisenbud, Reeves and Totaro proved the following result in [6].

Theorem 1. Let I be a monomial ideal with deg(I)=d and ed be an integer such that Ie is stable, then reg(I)e.

In [2], the authors gave the following bound for the regularity of Borel type ideals.

Proposition 1. Let I be a Borel type ideal, then reg(I)q(I).

Remark 1. As Ass(S/ID(G)) is totally ordered under inclusion, therefore ID(G) is a Borel type ideal by [2].

In [2], the authors proved the following:

Proposition 2. If I and J are two monomial ideals with sdeg(I) and tdeg(J) be two integers such that Is and Jt are stable ideals, then (IJ)max{s,t} is stable ideal.

3. Main Results

In this section, we give our main results regarding the Castelnuovo–Mumford regularity of elimination ideals for different classes of graphs.

3.1. Regularity of Regular Harary Graph Hn2,n

First, we recall the definition of Harary graph.

Definition 5.

Harary graph Hk,n is the smallest k-connected graph with n vertices. Let us have a set V={x1,x2,,xn} of n vertices, then the construction of Harary graphs are as follows:
Case I: If k=2m<n (n may be even or odd), then place all n vertices in a circle and join each vertex xi to its m consecutive left vertices and to its m consecutive right vertices by drawing edges.
Case II: Let n is even. If k=2m+1<n, then first construct H2m,n and then join each vertex xi, 1in2, to its diametrically opposite vertex.
Case III: If both k and n are odd then first construct Hk1,n, then join each vertex xi, 1in12+1, with vertex xi+n12.  

Note that the graphs in Case I and Case II are regular. Also note that if k=n1 then Case I and Case II suggest that Hk,n is a complete graph Kn. When n is even, the diametrically opposite vertex of xi is given by: {xixi+n2if 1in2xixin2if n2+1in

We are interested in computing the regularity of elimination ideal associated to Hn2,n when n is even and degree k=n2. We begin by computing the graphical degree stability of Hn2,n.

Lemma 1. Let Hn2,n be a regular Harary graph with even vertices n=2r4 and degree of each vertex is n2, then Stabd(Hn2,n)=n3.

Proof. We prove it by induction on r for n=2r4. For r=2, G0:=H2,4 is a regular graph with degree sequence (2,2,2,2), so its dominating set will be D(G0)={x1,x2,x3,x4}. Now, pick vertex x1D(G0), after removing x1 we get G1 with degree sequence (2,1,1). The process will stop at G1 and Stabd(H2,4)=1. 

Consider the result is true for r=p, i.e. Stabd(H2p2,2p)=2p3. 

Now take r=p+1, and let G0:=H2p,2p+2. The degree sequence of G0 is (2p,,2p)(2p+2)-tuple with dominating set is D(G0)={x1,x2,,x2p+2}. Choose vertex x1 from D(G0) and apply DVE method, we get G1 with D(G1) solely consists of diametrically opposite vertex (see Definition 1) of x1 of degree 2p. All other vertices are of degree p1. The degree sequence of G1 will be (2p,2p1,,2p1)(2p+1)-tuple. On removing x1 (after relabeling of the vertices) we get G2:=H2p2,2p. Now Stabd(H2p2,2p)=2p3 Stabd(H2p,2p+2)=2+Stabd(H2p2,2p)=(2p+2)3 which is required. 

Example 1. 1] Consider H4,6, here n=6 and k=4, see Figure 1. 

Corollary 2. Let Hn2,n be a regular Harary graph with even vertices n4 and degree of each vertex is n2, then its sequential ideal is given as follows: Qi={x1ni2,x2ni2,,xnini2if i is evenx1ni1,x2ni2,,xnini2if i is odd where 0in3.

Proof. The proof follows from the definition of elimination ideal and lemma 1

Theorem 2. Let Hn2,n be a regular Harary graph with even vertices n4 and degree of each vertex is n2, then reg(ID(Hn2,n))(n1)(n2)1.

Proof. We shall discuss the two cases of corollary 2 separately. 

Case 1. When i{0,2,4,,n4}, the sequential ideal is given as Qi=x1a1,,xniani where aj=ni2 for all 1jni. Let γ(i)=ai(ai+1)1 for all i{0,2,4,,n4}. We shall show that Qiγ(i) is a stable ideal. Take uQiγ(i), then u=vxkak for some 1kni where vx1,,xniγ(i)ak

If m(u)>k, then xluxm(u)=xlvxm(u)xkakQiγ(i) for all l<m(u). So, Qiγ(i) is stable. 

If m(u)=k, then clearly ux1,,xniγ(i) which is a stable ideal and Qiγ(i)x1,,xniγ(i). It remains to show that x1,,xniγ(i)Qiγ(i). Let wx1,,xniγ(i) then w=x1β1x2β2xniβni with βs0 for all 1sni and Σs=1niβsγ(i). Therefore, there exist at least one r{1,,ni} such that βrar and w=(x1β1xrβrarxniβni)xrarQiγ(i), hence the result follows. 

Case 2. When i{1,3,5,,n3}, the sequential ideal then is given as Qi=x1a1,,xniani where aj={ni1if j=1ni2if 2jni Let γ(i)=ai(ai+1) for all i{1,3,5,,n3}, then we shall show that Qiγ(i) is a stable ideal. Take uQiγ(i), then u=vxkak for some 1kni where vx1,,xniγ(i)ak

If m(u)>k, then xluxm(u)=xlvxm(u)xkakQiγ(i) for all l<m(u). So, Qiγ(i) is stable. 

If m(u)=k, then clearly ux1,,xniγ(i) which is stable ideal and Qiγ(i)x1,,xniγ(i). We are to show that x1,,xniγ(i)Qiγ(i). Let wx1,,xniγ(i) then w=x1β1x2β2xniβni with βs0 for all 1sni and Σs=1niβsγ(i). Therefore, there exist at least one r{1,,ni} such that βrar and w=(x1β1xrβrarxniβni)xrarQiγ(i) and the result follows. 

By lemma 1, Stabd(Hn2,n)=n3, so the corresponding elimination ideal is given as ID(Hn2,n)=i=0n3Qi. By proposition 1, ID(Hn2,n) is stable for γ0, where γ0=max{γ(i),γ(j)|i{0,2,,n4},j{1,3,,n3}}=(n1)(n2)1 and by theorem 1 reg(ID(Hn2,n))(n1)(n2)1. 

Remark 2. In Example 1,
D(G0)={x1,x2,,x6} with Q0=x14,x24,,x64 and reg(Q0)=19

D(G1)={x1} with Q1=x14,x23,,x53 and reg(Q1)=12 

D(G2)={x1,x2,x3,x4} with Q2=x12,x22,x32,x42 and reg(Q2)=5 

D(G3)={x1} with Q3=x12,x2,x3 and reg(Q3)=2

3.2. Regularity of KnPm

In [3], following formula is given to compute the graphical degree stability of path graph:

Proposition 3. Let Pm, m3, be a path graph then: Stabd(Pm)={m33if m0 (mod 3)m43if m1 (mod 3)m23if m2 (mod 3)

Lemma 1. Let Kn,n2 be a complete graph and Pm, m4 be a path graph then: Stabd(KnPm)=n+Stabd(Pm)

Proof. We shall prove it by induction on n. Let n=2 and m=4, then G0:=K2P4 with degree sequence (5,5,4,4,3,3) and D(G0)={x1,x2}. Without loss of generality, remove x1D(G0) to get G1 with the degree sequence (4,3,3,2,2). So, D(G1)={x1} and on removing x1D(G1), we get G2=P4.    Stabd(K2P4)=2+Stabd(P4) Suppose that result is true for n=q and m=r, then Stabd(KqPr)=q+Stabd(Pr)

Consider n=q+1 and m=r then G0:=Kq+1Pr with degree sequence (q+r,,q+r(q+1)-tuple,q+3,,q+3(r-2)-tuple,q+2,q+2) and |V(G0|=q+r+1. Since r4, D(G0)={x1,,xq+1} which are precisely the vertices that were initially belonged to Kq+1. As removing any vertex from Kq+1 gives Kq, So without loss of generality pick x1D(G0) and on removing it, we get G1=KqPr.    Stabd(Kq+1Pr)=1+Stabd(KqPr)=1+q+Stabd(Pr) which completes the proof. 

Corollary 3. Let Kn,n2 be a complete graph and Pm,m4 be a path graph, then the sequential ideal of KnPm is given as follows: Qi={x1m+ni1,,xnim+ni1,xni+1ni+2,,xm+ni2ni+2,xm+ni1ni+1,xm+nini+1if 0in1x12,x22,,xm3(in)22,xm3(in)1,,xm+niif nin+p where p=Stabd(Pm)

Proof. The proof follows immediately from lemma 1 and [3]. 

Theorem 3. Let Kn,n2 be a complete graph and Pm,m4 be a path graph then reg(ID(KnPm))n2+2n(m1)+m1.

Proof. We shall discuss the two cases of corollary 3 separately. 

Case 1. When 0in1, the sequential ideal is given as Qi=x1a1,,xm+niam+ni where aj={m+ni+1if 1jnini+2if ni+1jm+ni2ni+1if ni+1jm+ni. 

Let γ(i)=(ni)2+2(m1)(ni)+m1 for all 0in1. We shall show that Qiγ(i) is a stable ideal. Take uQiγ(i), then u=vxkak for some 1km+ni where vx1,,xm+niγ(i)ak

If m(u)>k, then xluxm(u)=xlvxm(u)xkakQiγ(i) for all l<m(u). So, Qiγ(i) is stable. 

If m(u)=k, then clearly ux1,,xm+niγ(i) and Qiγ(i)x1,,xm+niγ(i). We are to show that x1,,xm+niγ(i)Qiγ(i). Let wx1,,xm+niγ(i) then w=x1β1x2β2xm+niβm+ni with βs0 for all 1sm+ni and Σs=1m+niβsγ(i). Therefore, there exist at least one r{1,,m+ni} such that βrar and w=(x1β1xrβrarxm+niβm+ni)xrarQiγ(i) and the result follows. 

Case 2. When nin+p, the sequential ideal is given as Qi=x1a1,,xm+niam+ni where aj={2if 1jm3(in)21if m3(in)1jm+ni. 

Let γ(i)=m3(in)1 for all nin+p, then we shall show that Qiγ(i) is a stable ideal. Take uQiγ(i), then u=vxkak for some 1km+ni where vx1,,xm+niγ(i)ak

If m(u)>k, then xluxm(u)=xlvxm(u)xkakQiγ(i) for all l<m(u). So, Qiγ(i) is stable. 

If m(u)=k, then clearly ux1,,xm+niγ(i) and Qiγ(i)x1,,xm+niγ(i). We are to show that x1,,xm+niγ(i)Qiγ(i). Let wx1,,xm+niγ(i) then w=x1β1x2β2xm+niβm+ni with βs0 for all 1sm+ni and Σs=1m+niβsγ(i). Therefore, there exist at least one r{1,,m+ni} such that βrar and w=(x1β1xrβrarxm+niβm+ni)xrarQiγ(i) and the result follows. 

By lemma 1, Stabd(KnPm)=n+p, so the corresponding elimination ideal is given as ID(KnPm)=i=0n+pQi, by proposition 1, ID(KnPm) is stable for γ0, where γ0=max{γ(i),γ(j)|0in1 and njn+p}=n2+2n(m1)+m1 and by theorem 1, reg(ID(KnPm))n2+2n(m1)+m1. 

Example 2. Consider K3P4, here n=3 and m=4. 

D(G0)={x1,x2,x3}, Q0=x16,x26,x36,x45,x55,x64,x74 and reg(Q0)=30, see Figure 2.

 

D(G1)={x1,x2}, Q1=x15,x25,x34,x44,x53,x63 and reg(Q1)=19, see Figure 3.

 

D(G2)={x1}, Q2=x14,x23,x33,x42,x52 and reg(Q2)=10, see Figure 4.

D(G3)={x1,x2}, Q3=x12,x22,x3,x4 and reg(Q3)=3, see Figure 5.

3.3. Regularity of complete bipartite graph Km,n

We recall the result about graphical degree stability of complete bipartite graph from [3]:

Proposition 4. Let Km,n be a complete bipartite graph with mn then:Stabd(Km,n)=n1

We generalize this result for complete n-partite graphs.

Lemma 1. Let Km1,,mn be a complete n-partite graph with mimj for 1i<jn, then Stabd(Km1,,mn)=mn+mn1++m21

Proof. We prove it by induction. For n=2, we have Km1,m2 with m1m2 then by proposition 4: Stabd(Km1,m2)=m21 Let the result is true for n=k1, i.e. Stabd(Km1,,mk1)=mk1+mk2++m21 with mimj if 1i<jk1

Consider G0:=Km1,,mk, be the complete kpartite graph and V(G0)=X1X2Xk, where each Xr={xr1,xr2,,xrmr} is an independent set with |Xr|=mr, 1rk. Further mimj if 1i<jk

If xXr, 1rk then degree of x would be m1++mr1+mr+1++mk. As mkmj for all 1jk1, hence XkD(G0). So, without loss of generality we pick the vertex xkmkXk, removing it will give us a new graph G1 with dominating set D(G1)=Xk{xkmk} with degree of each vertex of D(G1) is still m1++mk1. If xXr, 1rk1 then degree of x in G1 would be m1++mr1+mr+1++mk1. Now pick xkmk1 from D(G1) and remove it so that we get new graph G2 with dominating set D(G2)=Xk{xkmk,xkmk1} with degree of each vertex of D(G2) is still m1++mk1. If xXr, 1rk1 then degree of x in G2 would be m1++mr1+mr+1++mk2. Continue in this way we get Gmk:=Km1,,mk1. So, Stabd(Km1,,mk)=mk+Stabd(Km1,,mk1)=mk+mk1++m21 which completes the proof. 

Corollary 1. Let Km,n be a complete bipartite graph with mn, then the sequential ideal is given as follows: Qi=x1m,,xnim,xni+1ni,,xm+nini where 0in1.

Proof. The proof follows immediately from lemma 1

Theorem 4. Let Km,n be a complete bipartite graph with mn, then reg(ID(Km,n))m+(2m1)(n1).

Proof. By proposition 4, Stabd(Km,n)=n1. The sequential ideal is given as Qi=x1a1,,xm+niam+ni for all 0in1 where aj={mif 1jniniif ni+1jm+ni. Let γ(i)=m+(2m1)(ni1) for all 0in1, then we shall show that Qiγ(i) is a stable ideal. Take uQiγ(i), then u=vxkak for some 1km+ni where vx1,,xm+niγ(i)ak

If m(u)>k, then xluxm(u)=xlvxm(u)xkakQiγ(i) for all l<m(u). So, Qiγ(i) is stable. 

If m(u)=k, then clearly ux1,,xm+niγ(i) and Qiγ(i)x1,,xm+niγ(i). We are to show that x1,,xm+niγ(i)Qiγ(i). Let wx1,,xm+niγ(i) then w=x1β1x2β2xm+niβm+ni with βs0 for all 1sm+ni and Σs=1m+niβsγ(i). Therefore, there exist at least one r{1,,m+ni} such that βrar and w=(x1β1xrβrarxm+niβm+ni)xrarQiγ(i) and the result follows. 

By proposition 1, ID(Km,n)=i=0n1Qi is stable for γ0, where γ0=max{γ(i)|0in1}=m+(2m1)(n1) and by theorem 1, reg(ID(Km,n))m+(2m1)(n1). 

Example 3. Consider K4,3, here m=4 and n=3.
D(G0)={x1,x2,x3}, Q0=x14,x24,x34,x43,x53,x63,x73 and reg(Q0)=18, see Figure 6.

D(G1)={x1,x2}, Q1=x14,x24,x32,x42,x52,x62 and reg(Q1)=11,see Figure 7.

D(G2)={x1}, Q2=x14,x2,x3,x4,x5 and reg(Q2)=4, see Figure 8.

Remark 3. As elimination ideals are of Borel type ideals and an upper bound for Borel type ideal were discussed in [2] and [1]. It is worthy to note that our given bounds are sharper than the one given in [2] and [7].

Acknowledgement

The first and second authors were supported by the Higher Education Commission (Islamabad) through the National Research Program for Universities, Grant No.7359/Punjab/NRPU/R&D/ HEC/ 2017.

Conflict of Interest

The author declares no conflict of interests.

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