Let f(n,k) be the maximum chromatic number among all graphs whose edge set can be covered by n copies of K(n), the complete graph on n vertices, so that any two of those K(n) share at most k vertices.It has been known that f(n,k)=(1–o(1)).n3/2 for k≥n1/2. We show that (1–o(1))n.k≤f(n,k)≤(k+1)(n−k) for k<n1/2, hence, for 1/k=o(1),f(n,k)=(1+o(1))n.k.