Inverse of α-Hermitian Adjacency Matrix of a Unicyclic Bipartite Graph

Omar Alomari1, Mohammad Abudayah2, Omar AbuGhneim3
1College of Engineering and Technology, American University of the Middle East, Kuwait
2School of Basic Sciences and Humanities, German Jordanian University, Madaba 11180, Jordan
3Department of Mathematics, Faculty of Science, The University of Jordan, Amman, Jordan

Abstract

Let X be bipartite mixed graph and for a unit complex number α, Hα be its α-hermitian adjacency matrix. If X has a unique perfect matching, then Hα has a hermitian inverse Hα1. In this paper we give a full description of the entries of Hα1 in terms of the paths between the vertices. Furthermore, for α equals the primitive third root of unity γ and for a unicyclic bipartite graph X with unique perfect matching, we characterize when Hγ1 is ±1 diagonally similar to γ-hermitian adjacency matrix of a mixed graph. Through our work, we have provided a new construction for the ±1 diagonal matrix.

Keywords: Mixed graphs, α-Hermitian adjacency matrix, Inverse matrix, Bipartite mixed graphs, Unicyclic bipartite mixed graphs, Perfect matching

1. Introduction

A partially directed graph X is called a mixed graph, the undirected edges in X are called digons and the directed edges are called arcs. Formally, a mixed graph X is a set of vertices V(X) together with a set of undirected edges E0(D) and a set of directed edges E1(X). For an arc xyE1(X), x(resp. y) is called initial (resp. terminal) vertex. The graph obtained from the mixed graph X after stripping out the orientation of its arcs is called the underlying graph of X and is denoted by Γ(X).

A collection of digons and arcs of a mixed graph X is called a perfect matching if they are vertex disjoint and cover V(X). In other words, perfect matching of a mixed graph is just a perfect matching of its underlying graph. In general, a mixed graph may have more than one perfect matching. We denote the class of bipartite mixed graphs with a unique perfect matching by H. In this class of mixed graphs the unique perfect matching will be denoted by M. For a mixed graph XH, an arc e (resp. digon) in M is called matching arc (resp. matching digon) in X. If D is a mixed subgraph of X, then the mixed graph XD is the induced mixed graph over V(X)V(D).

Studying a graph or a digraph structure through properties of a matrix associated with it is an old and rich area of research. For undirected graphs, the most popular and widely investigated matrix in literature is the adjacency matrix. The adjacency matrix of a graph is symmetric, and thus diagonalizable and all of its eigenvalues are real. On the other hand, the adjacency matrix of directed graphs and mixed graphs is not symmetric and its eigenvalues are not all real. Consequently, dealing with such matrix is very challenging. Many researchers have recently proposed other adjacency matrices for digraphs. For instance in [1], the author investigated the spectrum of AAT, where A is the traditional adjacency matrix of a digraph. The author called them non negative spectrum of digraphs. In [2], authors proved that the non negative spectrum is totally controlled by a vertex partition called common out neighbor partition. Authors in [3] and in [4] (independently) proposed a new adjacency matrix of mixed graphs as follows:

For a mixed graph X, the hermitian adjacency matrix of X is a |V|×|V| matrix H(X)=[huv], where

huv={1if uvE0(X),iif uvE1(X),iif vuE1(X),0otherwise.

This matrix has many nice properties. It has real spectrum and interlacing theorem holds. Beside investigating basic properties of this hermitian adjacency matrix, authors proved many interesting properties of the spectrum of H. This motivated Mohar in [5] to extend the previously proposed adjacency matrix. The new kind of hermitian adjacency matrices, called α-hermitian adjacency matrices of mixed graphs, are defined as follows: Let X be a mixed graph and α be the primitive nth root of unity e2πni. Then the α hermitian adjacency matrix of X is a |V|×|V| matrix Hα(X)=[huv], where

huv={1if uvE0(D),αif uvE1(D),α¯if vuE1(D),0otherwise.

Clearly the new kind of hermitian adjacency matrices of mixed graphs is a natural generalization of the old one for mixed graphs and even for the graphs. As we mentioned before these adjacency matrices (Hi(X) and Hα(X)) are hermitian and have interesting properties. This paved the way to more a facinating research topic much needed nowadays.

For simplicity when dealing with one mixed graph X, then we write Hα instead of Hα(X).

The smallest positive eigenvalue of a graph plays an important role in quantum chemistry. Motivated by this application, Godsil in [6] investigated the inverse of the adjacency matrix of a bipartite graph. He proved that if T is a tree graph with perfect matching and A(T) is its adjacency matrix then, A(T) is invertabile and there is {1,1} diagonal matrix D such that DA1D is an adjacency matrix of another graph. Many of the problems mentioned in [6] are still open. Further research appeared after this paper that continued on Godsil’s work see [7], [8] and [9].

In this paper we study the inverse of α-hermitian adjacency matrix Hα of unicyclic bipartite mixed graphs with unique perfect matching X. Since undirected graphs can be considered as a special case of mixed graphs, the out comes in this paper are broader than the work done previously in this area. We examine the inverse of α-hermitian adjacency matricies of bipartite mixed graphs and unicyclic bipartite mixed graphs. Also, for α=γ, the primative third root of unity, we answer the traditional question, when Hα1 is {±1} diagonally similar to an α-hermitian adjacency matrix of mixed graph. To be more precise, for a unicyclic bipartite mixed graph X with unique perfect matching we give full characterization when there is a {±1} diagonal matrix D such that DHγ1D is an γ-hermitian adjacency matrix of a mixed graph. Furthermore, through our work we introduce a construction of such diagonal matrix D. In order to do this, we need the following definitions and theorems:

Definition 1. [10] Let X be a mixed graph and Hα=[huv] be its α-hermitian adjacency matrix.

  • X is called elementary mixed graph if for every component X of X, Γ(X) is either an edge or a cycle Ck (for some k3).

  • For an elementary mixed graph X, the rank of X is defined as r(X)=nc, where n=|V(X)| and c is the number of its components. The co-rank of X is defined as s(X)=mr(X), where m=|E0(X)E1(X)|.

  • For a mixed walk W in X, where Γ(W)=r1,r2,rk, the value hα(W) is defined as hα(W)=hr1r2hr2r3hr3r4hrk1rk{αn}nZ

Recall that a bijective function η from a set V to itself is called permutation. The set of all permutations of a set V, denoted by SV, together with functions composition form a group. Finally recall that for ηSV, η can be written as composition of transpositions. In fact the number of transpositions is not unique. But this number is either odd or even and cannot be both. Now, we define sgn(η) as (1)k, where k is the number of transposition when η is decomposed as a product of transpositions. The following theorem is well known as a classical result in linear algebra.

Theorem 1. If A=[aij] is an n×n matrix then det(A)=ηSnsgn(η)a1,η(1)a2,η(2)a3,η(3)an,η(n).

2. Inverse of α-Hermitian Adjacency Matrix of a Bipartite Mixed Graph

In this section, we investigate the invertibility of the α-hermitian adjacency matrix of a bipartite mixed graph X. Then we find a formula for the entries of its inverse based on elementary mixed subgraphs. This will lead to a formula for the entries based on the type of the paths between vertices. Using Theorem 1, authors in [10] proved the following theorem:

Theorem 2. (Determinant expansion for Hα) [10] Let X be a mixed graph and Hα its α-hermitian adjacency matrix, then det(Hα)=X(1)r(X)2s(X)Re(Chα(C)), where the sum ranges over all spanning elementary mixed subgraphs X of X, the product ranges over all mixed cycles C in X, and C is any mixed closed walk traversing C.

Now, let XH and M is the unique perfect matching in X. Then since X is bipartite graph, X contains no odd cycles. Now, let Ck be a cycle in X, then if CkM is a perfect matching of Ck then, MΔCk=MCkCkM is another perfect matching in X which is a contradiction. Therefore there is at least one vertex of Ck that is matched by a matching edge not in Ck. This means if XH, then X has exactly one spanning elementary mixed subgraph that consist of only K2 components. Therefore, Using the above discussion together with Theorem 2 we get the following theorem:

Theorem 3. If XH and Hα is its α-hermitian adjacency matrix then Hα is non singular.

Now, Let X be a mixed graph and Hα be its α-hermitian adjacency matrix. Then, for invertible Hα, the following theorem finds a formula for the entries of Hα1 based on elementary mixed subgraphs and paths between vertices. The proof can be found in [11].

Theorem 4. Let X be a mixed graph, Hα be its α-hermitian adjacency matrix and for ij, ρij={Pij:Pij is a mixed path from the vertex i to the vertex j}. If det(Hα)0, then ij=1det(Hα)Pijρij(1)|E(Pij)| hα(Pij)X(1)r(X)2s(X)Re(Chα(C)), where the second sum ranges over all spanning elementary mixed subgraphs X of XPij, the product is being taken over all mixed cycles C in X and C is any mixed closed walk traversing C.

This theorem describes how to find the non diagonal entries of Hα1. In fact, the diagonal entries may or may not equal to zero. To observe this, lets consider the following example:

Example 1. Consider the mixed graph X shown in Figure 1 and let α=eπ5i. The mixed graph X has a unique perfect matching, say M, and this matching consists of the set of unbroken arcs and digons. Further M is the unique spanning elementary mixed subgraph of X. Therefore, using Theorem 2 det[Hα]=(1)84244=1. So, Hα is invertible. To calculate [Hα1]ii, we observe that [Hα1]ii=det((Hα)(i,i))det(Hα)=det((Hα)(i,i)), where (Hα)(i,i) is the matrix obtained from Hα by deleting the ith row and ith column, which is exactly the α-hermitian adjacency matrix of X{i}. Applying this on the mixed graph, one can deduce that the diagonal entries of Hα1 are all zeros except the entry (Hα1)11. In fact it can be easily seen that the mixed graph X{1} has only one spanning elementary mixed subgraph. Therefore, [Hα1]11=det((Hα)(1,1))=(1)72265Re(α)=2Re(α).

The following theorem shows that if X is a bipartite mixed graph with unique perfect matching, then the diagonal entries of Hα1 should be all zeros.

Theorem 5. Let XH and Hα be its α-hermitian adjacency matrix. Then, for every vertex iV(X), (Hα1)ii=0.

Proof. Observing that X is a bipartite mixed graph with a unique perfect matching, and using Theorem 3, we have Hα is invertable. Furthermore, (Hα1)ii=det((Hα)(i,i))det(Hα).

Note that (Hα)(i,i) is the α-hermitian adjacency matrix of the mixed graph X{i}. However X has a unique perfect matching, therefore X{i} has an odd number of vertices. Hence X{i} has neither a perfect matching nor an elementary mixed subgraph and thus det((Hα)(i,i))=0◻

Now, we investigate the non diagonal entries of the inverse of the α-hermitian adjacency matrix of a bipartite mixed graph, XH. In order to do that we need to characterize the structure of the mixed graph XP for every mixed path P in X. To this end, consider the following theorems:

Theorem 6. [12]Let M and M be two matchings in a graph G. Let H be the subgraph of G induced by the set of edges MΔM=(MM)(MM). Then, the components of H are either cycles of even number of vertices whose edges alternate in M and M or a path whose edges alternate in M and M and end vertices unsaturated in one of the two matchings.

Corollary 1. For any graph G, if G has a unique perfect matching then G does not contain alternating cycle.

Definition 2. Let X be a mixed graph with unique perfect matching. A path P between two vertices u and v in X is called co-augmenting path if the edges of the underlying path of P alternates between matching edges and non-matching edges where both first and last edges of P are matching edges.

Corollary 2. Let G be a bipartite graph with unique perfect matching M, u and v are two vertices of G. If Puv is a co-augmenting path between u and v, then GPuv is a bipartite graph with unique perfect matching MPuv.

Proof. The part that MPuv is being a perfect matching of GPuv is obvious. Suppose that MMPuv is another perfect matching of GPuv. Using Theorem 6, GPuv consists of an alternating cycles or an alternating paths, where its edges alternate between MPuv and M. If all GPuv components are paths, then GPuv has exactly one perfect matching, which is a contradiction. Therefore, GPuv contains an alternating cycle say C. Since Puv is a co-augmenting path, we have M(PuvM) is a perfect matching of G. Therefore G has more than one perfect matching, which is a contradiction. ◻

Theorem 7. Let G be a bipartite graph with unique perfect matching M, u and v are two vertices of G. If Puv is not a co-augmenting path between u and v, then GPuv does not have a perfect matching.

Proof. Since G has a perfect matching, then G has even number of vertices. Therefore, when Puv has an odd number of vertices, GPuv does not have a perfect matching.

Suppose that Puv has an even number of vertices. Then, Puv has a perfect matching M. Therefore if GPuv has a perfect matching M, then MM will form a new perfect matching of G. This contradicts the fact that G has a unique perfect matching. ◻

Now, we are ready to give a formula for the entries of the inverse of α-hermitian adjacency matrix of bipartite mixed graph X that has a unique perfect matching. This characterizing is based on the co-augmenting paths between vertices of X.

Theorem 8. Let X be a bipartite mixed graph with unique perfect matching M, Hα be its α-hermitian adjacency matrix and ij={Pij:Pij\small{ is a co-augmenting mixed path from the vertex }i to the vertex j}. Then

(Hα1)ij={Pijij(1)|E(Pij)|12hα(Pij)if ij,0 if i=j.

Proof. Using Theorem 4, [Hα1]ij=1det(Hα)Pijρij[(1)|E(Pij)|hα(Pij)X(1)r(X)2s(X)Re(Chα(C))], where the second sum ranges over all spanning elementary mixed subgraphs of XPij. The product is being taken over all mixed cycles C of X and C is any mixed closed walk traversing C.

First, using Theorem 7 we observe that if Pij is not a co-augmenting path then XPij does not have a perfect matching. Therefore, the term corresponds to Pij contributes zero. Thus we only care about the co-augmenting paths. According to Corollary 2, for any co-augmenting path Pij from the vertex i to the vertex j we get XPij has a unique perfect matching, namely ME(XPij). Using Corollary 1, XPij does not contain an alternating cycle. Thus XPij contains only one spanning elementary mixed subgraph which is MPij. So,

[Hα1]ij=1det(Hα)Pijij(1)|E(Pij)|hα(Pij)(1)V(XPij)k, where k is the number of components of the spanning elementary mixed subgraph of XPij. Observe that |V(XPij)|=n(|E(Pij)|+1), k=n(|E(Pij)|+1)2 and det(Hα)=(1)n2, we get the result. ◻

3. Inverse of γ-hermitian Adjacency Matrix of a Unicyclic Bipartite Mixed Graph

Let γ be the third root of unity e2π3i. Using Theorem 8, hα(Pij){αi}i=1n plays a central rule in finding the entries of Hα1 and since the third root of unity has the property γi{1,γ,γ¯} we focus our study in this section on α=γ. The property that αi{±1,±α,±α¯} is not true in general. To illustrate, consider the mixed graph shown in Figure 2 and let α=eπ5i. Using Theorem 1 we get H051=e3π5i which is not from the set {±1,±α,±α¯}.

In this section, we are going to answer the classical question whether the inverse of γ-hermitian adjacency matrix of a unicyclic bipartite graph is {1,1} diagonally similar to a hermitian adjacency matrix of another mixed graph or not. Consider the mixed graph shown in Figure 2. Then, obviously entries of Hγ1 are from the set {0,±1,±γ,±γ¯}.

Another thing we should bear in mind is the existence of {1,1} diagonal matrix D such that DHγD is γ-adjacency matrix of another mixed graph. In the mixed graph X in Figure 2, suppose that D=diag{d0,d1,,d9} is {1,1} diagonal matrix with the property DHγD has all entries from the set {0,γ,γ¯}. Then, d0d5=1,d0d9=1,d9d7=1,d5d7=1, which is impossible. Therefore, such diagonal matrix D does not exist. To discuss the existence of the diagonal matrix D further, let G be a bipartite graph with unique perfect matching. Define XG to be the mixed graph obtained from G by orienting all non matching edges. Clearly for α1 and α1 changing the orientation of the non matching edges will change the α-hermitian adjacency matrix. For now lets restrict our study on α=1. Using Theorem 8 one can easily get the following observation.

Observation 1. Let G be a bipartite mixed graph with unique perfect matching M, H1 be the 1-hermitian adjacency matrix of XG and ij={Pij:Pij is a co-augmenting mixed path from the vertex i to the vertex j in XG}. One can use Theorem 8 to get

(H11)ij={|ij|if ij,0 if i=j.

So, the question we need to answer now is when A(G) and H1(XG) are diagonally similar. To this end, let G be a bipartite graph with a unique perfect matching and uV(G). Then for a walk W=u=r1,r2,r3,,rk in G, define a function that assign the value fW(j) for the jth vertex of W as follows: fW(1)=1 and fW(j+1)={fW(j)if rjrj+1is unmatching edge in G,fW(j)if rjrj+1is matching edge in G,

See Figure 3.

Since any path from a vertex u to itself consist of pairs of identical paths and cycle, we get the following remark:

Remark 1. Let G be bipartite graph with unique perfect matching and F(u)={fW(u):W is aclosed walk in G starting at u}. then, |F(u)|=1 if and only if the number of unmatching edges in each cycle of G is even.

Finally, let G be a bipartite graph with unique perfect matching and suppose that each cycle of G has an even number of unmatched edges. For a vertex uV(G) define the function w:V(G){1,1} by w(v)=fW(v), where W is apath from u to v.

Definition 3. Suppose that G is bipartite graph with unique perfect matching and every cycle of G has even number of unmatched edges. Suppose further V(G)={v1,v2,,vn} and uV(G). Define the matrix Du by Du=diag{w(v1),w(v2),,w(vn)}.

Theorem 9. Suppose G is a bipartite graph with unique perfect matching and every cycle of G has an even number of unmatched edges. Then for every uV(G), we get DuA(G)Du=H1(XG).

Proof. Note that, for x,yV(G), we have (DuA(G)Du)xy=dxaxydy. Using the definition of Du we get,

dxdy={1if xy is an unmatching edge in G,1if xy is a matching edge in G,0 otherwise. Therefore, (DuA(G)Du)xy=(H1)xy◻

Now we are ready to discuss the inverse of γ-hermitian adjacency matrix of unicyclic mixed graph. Let X be a unicyclic bipartite graph with unique perfect matching. An arc or digon of X is called a peg if it is a matching arc or digon and incident to a vertex of the cycle in X. Since X is unicyclic bipartite graph with unique perfect matching, X has at least one peg. Otherwise the cycle in X will be alternate cycle, and thus X has more than one perfect matching which contradicts the assumption. Since each vertex of the cycle incident to a matching edge and |V(X)| is even, X should contain at least two pegs. The following theorem will deal with unicyclic bipartite mixed graphs XH with more than two pegs.

Theorem 10. Let X be a unicyclic bipartite graph with unique perfect matching. If X has more than two pegs, then between any two vertices of X there is at most one co-augmenting path.

Proof. Let ρ1,ρ2 and ρ3 be three pegs in X, u,vV(D), C is the unique cycle in X and suppose there are two co-augmenting paths between u and v, say P and P. Since X is unicyclic, we have V(C)PP,

  1. Case 1: E(P)E(P) does not contain any of the pegs. Then, if v is the X cycle vertex incident to ρ1 then, v is not matched by an edge in the cycle, which means one of P or P is not co-augmenting path, which contradicts the assumption.

  2. Case 2: (E(P)E(P) contain pegs. Then, (E(P)E(P) should contain at most two pegs, suppose that ρ1 and v is the vertex of X cycle that incident to ρ1. Then, v belongs to either P or P, again since ρ1 is a matched edge, v is not matched by the cycle edges which means one of P or P is not co-augmenting path. which contradicts the assumption.

 ◻

Corollary 3. Let X be a unicycle bipartite mixed graph with unique perfect matching. If X has more than two pegs, then

  1. (Hα1)ij={(1)|E(Pij)|12hα(Pij)if Pij is a co-augmenting path from i to j,0 Otherwise.

  2. If the cycle of X contains even number of unmatching edges, then for any vertex uV(X), DuHγ1(X)Du is γ-hermitian adjacency matrix of a mixed graph.

Proof. Part one is obvious using Theorem 8 together with Theorem 11.

For part two, we observe that γi{1,γ,γ¯}. Therefore all Hγ1(X) entries are from the set {±1,±γ,±γ¯}. Also the negative signs in A(Γ(X))1 and in Hγ1 appear at the same position. Which means DuHγ1Du is γ-hermitian adjacency matrix of a mixed graph if and only if DuA(Γ(X))Du is adjacency matrix of a graph. Finally, Theorem 1 ends the proof. ◻

Now we will take care of unicycle graph with exactly two pegs. Using the same technique of the proof of Theorem 11, one can show the following:

Theorem 11. Let D be a unicyclic bipartite graph with unique perfect matching and exactly two pegs ρ1 and ρ2. Then for any two vertices of D, u and v, if there are two co-augmenting paths from the vertex u to the vertex v, then ρ1 and ρ2 are edges of the two paths.

Let X be a unicyclic bipartite mixed graph with unique perfect matching and exactly two pegs, and let uv and uv be the two pegs of X where v and v are vertices of the cycle of X. We, denote the two paths between v and v by Fvv and Fvvc.

Theorem 12.

Let X be a unicyclic bipartite mixed graph with unique perfect matching and exactly two pegs and let C be the cycle of X. If there are two coaugmenting paths between the vertex x and the vertex y, then

(Hα1)xy=(1)|E(Pxy)|12hα(Pxv)hα(Pyv)hα(Fvv)[(1)m+1hα(C)+1], where Fvv is chosen to be the part of the path Pxy in the cycle C and C is of size 2m.

Proof. Suppose that Pxy and Qxy are the paths between the vertices x and y, using theorem 8 we have

(Hα1)xy=(1)|E(Pxy)|12hα(Pxy)+(1)|E(Qxy)|12hα(Qxy).

Now, using Theorem 11, Pxy (Qxy) can be divided into three parts Pxv, Fvv and Pvy (resp. Qxv=Pxv, Fvvc and Qvy=Pvy).
Observe that the number of unmatched edges in Fvv is k1=|E(Fvv)|+12 and the number of unmatched edges in Fvvc is k2=m|E(Fvv)|+12+1 we get

(Hα1)xy=(1)khα(Pxv)hα(Pvy)((1)k1hα(Fvv)+(1)k2hα(Fvvc)), where k=|E(Pxv)|+|E(Pvy)|21.

Note here hα(Fvv)¯hα(Fvvc)=hα(C), therefore, (Hα1)xy=(1)|E(Pxy)|12hα(Pxv)hα(Pyv)hα(Fvv)[(1)m+1hα(C)+1]. ◻

Theorem 13. Let X be a unicyclic bipartite mixed graph with unique perfect matching and Hγ be its γ-hermitian adjacency matrix. If X has exactly two pegs, then Hγ1 is not ±1 diagonally similar to γ-hermitian adjacency matrix of a mixed graph.

Proof. Let xx and yy be the two pegs of X, where x and y are vertices of the cycle C of X . Then, using Theorem 12 we have (Hγ1)xy=(1)|E(Pxy)|12hγ(Pxx)hγ(Pyy)hγ(Fxy)[(1)m+1hγ(C)+1], where Fxy is chosen to be the part of the path Pxy in the cycle C and C is of size 2m. Suppose that D=diag{dv:vV(X)} is a {±1} diagonal matrix with the property that DHγ1D is γ-hermitian adjacency matrix of a mixed graph.

  1. Case 1: Suppose m is even say m=2r.

    Observe that (1)m+1hγ(C)+1=1hγ(C). If hγ(C){1,γ,γ2}, then 1hγ(C){±1,±γ,±γ2} and so Hγ1 is not ±1 diagonally similar to γ-hermitian adjacency matrix of a mixed graph. Thus we only need to discuss the case when hγ(C)=1. To this end, suppose that hγ(C)=1. Then (Hγ1)xy=0. Since the length of C is 4r, we have the number of unmatching edges (number of matching edges) in C is 4r+22 (resp. 4r22). Since the number of unmatching edges in C is odd, there is a coaugmenting path Fxy from x to y that contains odd number of unmatching edges and another coaugmenting path Fxyc with even number of unmatching edges. Now, let oo(ee ) be any matching edges in the path Fxy (resp. Fxyc). Then, without loss of generality we may assume that there is a coaugmenting path between x and e, x and o (and hence there is a co-augmenting path between y and o, y and e ). Now, if dxdy=1 then

    • (DHγ1D)xo=(1)kdxhγ(Pxo)do

    • (DHγ1D)yo=(1)kdyhγ(Pyo)do

    Observe that k+k is odd number, we have dodo=1. This contradict the fact that for every matching edge gg, dgdg=1. The case when dxdy=1 is similar to the above case but with considering the path Fxyc instead of Fxy and the vertex e instead of o.

  2. Case 2:Suppose m is odd say 2r+1. Then (Hγ1)xy=(1)|E(Pxy)|12hα(Pxv)hα(Pyv)hα(Fvv)[hα(C)+1]. Therefore, (Hγ1)xy=(1)|E(Pxy)|12hα(Pxv)hα(Pyv)hα(Fvv){γif hα(C)=γ2,γ2if hα(C)=γ,2if hα(C)=1. Obviously, when hα(C)=1, Hγ1 is not ±1 diagonally similar to γ-hermitian adjacency matrix of a mixed graph. Thus, the cases we need to discuss here are when hα(C)=γ and hα(C)=γ2.

    Since m is odd, then C contains an even number of unmatched edges. Therefore, either both paths between x and y, Fxy and Fxyc, contain odd number of unmatching edges or both of them contains even number of unmatching edges.

    To this end, suppose that both of the paths Fxy and Fxyc contain odd number of unmatched edges. Then, (Hγ1)xy{γi}i=02, which means dxdy=1. Finally, let vv be any matching edge in Fxy where Pxv and Pvy are coaugmenting paths, then obviously dvdv=1. But one of the coaugmenting paths Pxv and Pvy should contain odd number of unmatching edges and the other one should contain even number of unmatched edges. Which means dxdvdvdy=1. This contradicts the fact that dvdv=1.

    In the other case, when both Fxy and Fxyc contain even number of unmatching edges, one can easily deduce that dxdy=1 and using same technique we can get another contradiction.

  3.  ◻

Note that Corollary 3 and Theorem 13 give a full characterization of a unicyclic bipartite mixed graph with unique perfect matching where the inverse of its γ-hermitian adjacency matrix is {±1} diagonally similar to γ-hermitian adjacency matrix of a mixed graph. We summarize this characterization in the following corollary.

Theorem 14. Let X be a unicyclic bipartite mixed graph with unique perfect matching and Hγ its γ-hermitian adjacency matrix. Then, Hγ1 is ±1 diagonally similar to γ-hermitian adjacency matrix if and only if X has more than two pegs and the cycle of X contains even number of unmatching edges.

Acknowledgments

We thank the anonymous referees for their helpful comments.

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