Multi-decomposition of graphs into paths and Y-trees of order five

Chaadhanaa A1, Hemalatha P1
1Department of Mathematics, Vellalar College For Women, Tamil Nadu, India

Abstract

Let Kn, Pn, and Yn respectively denote a complete graph, a path, and a Y-tree on n vertices, and let Km,n denote a complete bipartite graph with m and n vertices in its parts. Graph decomposition is the process of breaking down a graph into a collection of edge-disjoint subgraphs. A graph G has a (H1,H2)-multi-decomposition if it can be decomposed into α0 copies of H1 and β0 copies of H2, where H1 and H2 are subgraphs of G. In this paper, we derive the necessary and sufficient conditions for the (P5,Y5)-multi-decomposition of Kn and Km,n.

Keywords: Path, Y-Tree, Multi-decomposition, Complete graph, Complete bipartite graph, Conjoined Twins

1. Introduction

All graphs considered in this paper are finite, simple, and undirected. Let Kn denote a complete graph on n vertices, Km,n a complete bipartite graph with vertex partite sets of cardinality m and n, and Pk a path on k vertices. A Y-tree on k vertices, denoted by Yk, is a tree in which one edge is attached to a vertex v of the path Pk1 such that at least one of the adjacent vertices of v has degree 1.

A decomposition of a graph G is a set of edge-disjoint subgraphs H1,H2,,Hr of G such that every edge of G belongs to exactly one Hi, 1ir. If all the subgraphs in the decomposition of G are isomorphic to a graph H, then G is said to be H-decomposable. If G can be decomposed into α copies of H1 and β copies of H2, then G is said to have an (H1,H2)-multi-decomposition or an {H1α,H2β}-decomposition. The pair (α,β) is called admissible if it satisfies the necessary conditions for the existence of an {H1α,H2β}-decomposition. If G has an (H1,H2)-multi-decomposition for all admissible pairs (α,β), it is said to have an (H1,H2){α,β}-decomposition.

The necessary and sufficient condition for the existence of a P5-decomposition of complete graphs was studied in [5], and for complete bipartite graphs in [1]. The path decomposition of various graphs was explored in [15,11]. The graph Y5 is one of the three non-isomorphic trees of order five, excluding paths and stars. Caterina and Antonio [3] named Y5 as the chair and studied the stability number of chair-free graphs.

The Y5-decomposition of complete graphs was obtained by C. Huang and A. Rosa [5]. J. Paulraj Joseph and A. Samuel Issacraj [8] referred to Y5 as the fork and studied its decomposition in complete bipartite graphs. S. Gomathi and A. Tamil Elakkiya [4] defined this graph as a Y5-tree and investigated its decomposition in the tensor product of complete graphs. The Y5-decomposition of various graphs was further analyzed in [9,10]. The concept of multi-decomposition was introduced by A. Abueida and M. Daven [2]. In recent years, multi-decomposition of graphs has emerged as a prominent research area in graph theory. T.-W. Shyu studied the multi-decomposition of complete graphs into paths with cycles and stars [12,13]. S. Jeevadoss and A. Muthusamy established necessary and sufficient conditions for the multi-decomposition of complete bipartite graphs into paths and cycles [6]. Multi-decomposition of complete bipartite graphs into paths and stars was considered in [14].

In this paper, we establish the necessary and sufficient conditions for the existence of a (P5,Y5)-multi-decomposition of Kn and Km,n. To prove our results, we recall the following theorems:

Theorem 1.1. [5] The complete graph Kn is Y5-decomposable if and only if n0(mod8).

Theorem 1.2. [1] Let k,m, and n be positive integers. The necessary conditions for a Pk+1-decomposition of Km,n are listed in Table 1, and these conditions are also sufficient.

Table 1 Necessary and sufficient conditions for a Pk+1-decomposition of Km,n
Case k m n Characterization
1. even even even k2m,k2n, not both equal
2. odd even even Equalities hold when k is even
3. even even odd k2m2,k2n
4. even odd even k2m,k2n2
5. even odd odd Decomposition impossible
6. odd even odd k2m1,kn
7. odd odd even km,k2n1
8. odd odd odd km,kn
Theorem 1.3. [8] The complete bipartite graph Km,n is fork-decomposable if and only if mn0(mod4), except for K2,4i+2, (i=1,2,).

2. Multi-decomposition of complete graphs into P5 and Y5

2.1. Preliminaries

Definition 2.1. [7] For a graph G, two disjoint subsets of vertices are called twins if they have the same order and induce subgraphs with the same number of edges.

Next, we introduce a new graph structure called Conjoined Twins in the following remark.

Remark 2.2. Consider the graph T with vertex set {vi:1i8}.

The subgraphs induced by A and B are isomorphic to P5 when A={v1,v2,v6,v7,v8} and B={v2,v3,v4,v5,v6}. Similarly, if A={v1,v2,v3,v4,v8} and B={v4,v5,v6,v7,v8}, the corresponding induced subgraphs are isomorphic to Y5. We call these subsets of vertices Conjoined Twins (T) because the subsets A and B are not disjoint (there are two common vertices), but the induced subgraphs are isomorphic.

It is interesting to note that the subgraph induced by A is isomorphic to P5 when A={v1,v2,v3,v8,v6}, and if B={v3,v4,v5,v6,v7}, the corresponding induced subgraph is isomorphic to Y5.

Thus, decomposing the graph G into a structure whose vertices are Conjoined Twins as in Figure 1 can be viewed as consisting of 2 copies of P5, 2 copies of Y5, or 1 copy each of P5 and Y5, which significantly simplifies the (P5,Y5)-multi-decomposition.

2.2. Notations

  • For a subgraph H of G, GH denotes a graph where V(GH)=V(G) and E(GH)=E(G)E(H).

  • rG denotes r disjoint copies of the graph G.

  • G=H1H2 means G can be decomposed into H1 and H2.

  • Let vi, 1in, be the vertices of the complete graph Kn.

  • In the complete bipartite graph Km,n, the vertices of the first partite set with m vertices are denoted by v1i, 1im, and the second partite set with n vertices by v2j, 1jn.

  • A path P5 with 5 vertices vi, 1i5, having v1 and v5 as pendant vertices is denoted by P5(v1,v2,v3,v4,v5).

  • The Y5 graph with 5 vertices vi, 1i5, is denoted by Y5(v1,v2,v3_,v4;v5_), where vi, 1i4, form a path of length three, and the underlined vertices denote an edge v3v5.

  • Suppose we have a graph whose vertices are Conjoined Twins (T) as in Figure 1. We denote it by T(v1,v2_,v3,v4,v5,v6_,v7;v8_), where vi, 1i7, form a path of length six, and the underlined vertices denote edges v2v8 and v6v8.

Remark 2.3. If two graphs G1 and G2 have an (H1,H2)-multi-decomposition, then G1G2 also has such a decomposition.

2.3. Necessary condition

The following theorem gives the necessary condition for the existence of a multi-decomposition of the complete graph Kn into paths and Y-trees with 5 vertices.

Theorem 2.4. If Kn has a (P5,Y5) – multi-decomposition, then n0or1(mod8).

Proof. Proof follows from the edge divisibility condition. ◻

2.4. Sufficient conditions

In this section, we show that the necessary condition obtained in Theorem 2.4 is also sufficient for the existence of a multi-decomposition of Kn, (n8) into P5 and Y5.

Lemma 2.5. The Complete graphs K8 and K9 have (P5,Y5) – multi-decomposition.

Proof. K8=3T1P5, where the 3T’s and 1P5 are given by, T(v6,v7_,v5,v1,v4,v8_,v2;v3_),T(v3,v6_,v4,v2,v5,v8_,v7;v1_),T(v8,v6_,v5,v3,v1,v7_,v4;v2_),P5(v1,v2,v3,v4,v5).

Similarly, K9 can be written as K9=4T1P5, where the 4T’s and 1P5 are as follows: T(v3,v6_,v4,v1,v8,v7_,v5;v2_),T(v3,v9_,v4,v2,v5,v6_,v1;v7_),T(v4,v8_,v5,v3,v1,v9_,v2;v6_),T(v4,v7_,v1,v5,v9,v8_,v2;v3_),P5(v1,v2,v3,v4,v5). ◻

Lemma 2.6. The Complete bipartite graphs K7,8, K8,8 and K9,8 have (P5,Y5) – multi-decomposition.

Proof. It is clear that K7,8=7T, where 7T’s are given by, T(v21,v11_,v23,v12,v24,v13_,v22;v25_),T(v25,v12_,v22,v11,v26,v13_,v23;v21_),T(v24,v11_,v28,v15,v26,v14_,v25;v27_),T(v24,v14_,v28,v13,v27,v15_,v25;v23_),T(v27,v12_,v28,v17,v24,v16_,v25;v26_),T(v28,v16_,v21,v14,v22,v17_,v26;v27_),T(v24,v15_,v22,v16,v23,v17_,v25;v21_).

Similarly K8,8=8T, where 8T’s are identified as, T(v22,v13_,v24,v12,v23,v18_,v21;v25_),T(v28,v12_,v25,v11,v26,v13_,v23;v27_),T(v26,v12_,v21,v13,v28,v14_,v25;v22_),T(v28,v11_,v27,v14,v26,v15_,v25;v24_),T(v24,v14_,v21,v16,v27,v15_,v22;v23_),T(v24,v16_,v28,v15,v21,v17_,v26;v22_),T(v21,v11_,v23,v17,v24,v18_,v27;v22_),T(v23,v16_,v26,v18,v28,v17_,v27;v25_).

Further K9,8=9T, the following are the required 9T’s T(v26,v11_,v23,v12,v24,v13_,v25;v22_),T(v25,v12_,v26,v19,v27,v13_,v23;v28_),T(v22,v12_,v21,v13,v26,v14_,v23;v27),T(v28,v11_,v24,v14,v22,v15_,v25;v27),T(v21,v14_,v25,v16,v23,v15_,v24;v28_),T(v27,v16_,v21,v15,v26,v17_,v22;v24_),T(v21,v18_,v27,v17,v25,v19_,v22;v24_),T(v22,v16_,v26,v18,v23,v17_,v21;v28_),T(v22,v18_,v25,v11,v21,v19_,v23;v28_). ◻

Lemma 2.7. The graph K8 admits (P5,Y5){α,β} – decomposition when α+β=7.

Proof. The admissible pairs satisfying α+β=7 are {(0,7),(1,6),(2,5),(3,4),(4,3),(5,2),
(6,1),(7,0)}.

Case 1. α0.

From Lemma 2.5, K8=3T1P5, which can be taken into any of the forms: 6Y51P5,5Y52P5,4Y53P5,3Y54P5,2Y55P5,1Y56P5,and7P5 using Remark 2.2.

Thus we have (P5,Y5) – multi-decomposition for the admissible pairs (α,β) {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1),(7,0)}.

Case 2. α=0.

Theorem 1.1 gives the required decomposition for the admissible pair (0,7).

Hence the proof follows from Cases 1 & 2 for all admissible pairs (α,β)◻

Lemma 2.8. The graph K9 admits (P5,Y5){α,β} – decomposition if α+β=9.

Proof. The admissible pairs satisfying α+β=9 are {(0,9),(1,8),(2,7),(3,6),(4,5),(5,4),
(6,3),(7,2),(8,1),(9,0)}.

Case 1. α0.

From Lemma 2.6, K9=4T1P5, which can be taken into any of the forms: 8Y51P5,7Y52P5,6Y53P5,5Y54P5,4Y55P5,3Y56P5,2Y57P5,1Y58P5and9P5 using Remark 2.2.

Thus we have (P5,Y5) – multi-decomposition for the admissible pairs (α,β) {(1,8),(2,7),(3,6),(4,5),(5,4),(6,3),(7,2),(8,1),(9,0)}.

Case 2. α=0.

Theorem 1.1 gives the required decomposition for the admissible pair (0,9).

Thus, K9 admits (P5,Y5){α,β} – decomposition. ◻

Lemma 2.9. The graph K7,8 admits (P5,Y5){α,β} – decomposition if α+β=14.

Proof. The admissible pairs satisfying α+β=14 are {(0,14),(1,13),(2,12),(3,11),(4,10),(5,9),(6,8),
(7,7),(8,6),(9,5),(10,4),(11,3),(12,2),(13,1),(14,0)}.

From Lemma 2.6, K7,8=7T, which can be taken into any of the forms: 14Y5,13Y51P5,12Y52P5,11Y53P5,10Y54P5,9Y55P5,8Y56P5,7Y57P5,6Y58P5,5Y59P5,4Y510P5,3Y511P5,2Y512P5,1Y513P5and14P5 using Remark 2.2.

Thus we have (P5,Y5) – multi-decomposition for all the admissible pairs (α,β)◻

Lemma 2.10. The graph K8,8 admits (P5,Y5){α,β} – decomposition if α+β=16.

Proof. The admissible pairs satisfying α+β=16 are {(0,16),(1,15),(2,14),(3,13),(4,12),(5,11),(6,10),
(7,9),(8,8),(9,7),(10,6),(11,5),(12,4),(13,3),(14,2),(15,1),(16,0)}.

From Lemma 2.6 , K8,8=8T. Then we have (P5,Y5) – multi-decomposition for all the admissible pairs (α,β) using Remark 2.2. ◻

Lemma 2.11. The graph K9,8 admits (P5,Y5){α,β} – decomposition when α+β=18.

Proof. The admissible pairs satisfying α+β=18 are {(0,18),(1,17),(2,16),(3,15),(4,14),(5,13),(6,12),(7,11),(8,10),(9,9),(10,8),(11,7),(12,6),(13,5),(14,4),(15,3),(16,2),(17,1),(18,0)}.

From Lemma 2.6 , K9,8=9T. Then we have (P5,Y5) – multi-decomposition for all the admissible pairs (α,β) using Remark 2.2. ◻

Theorem 2.12. (Sufficient conditions) For given non negative integers α, β and n8, Kn has (P5,Y5){α,β} – decomposition whenever 4(α+β)=(n2).

Proof. From the given (Necessary conditions) edge divisibility condition,
we have n0or1(mod8).

Case 1: n0(mod8).

Let n=4t, t is even. We prove this theorem using induction on t. When t=2, the proof follows from Lemma 2.7. We observe that for t4, (1)K4t=K4(t2)K9K4(t2)1,8.

Also for t6, (2)K4(t2)1,8=K4(t4)1,8K8,8.

From (1) and (2), (3)K4t=K4(t2)K9K4(t4)1,8K8,8,t6.

Assume that the theorem is true for all even k < t. We have to prove for t=k+2. From (3), we can write, K4(k+2)=K4kK9K4(k2)1,8K8,8.

By induction hypothesis and from Lemmas 2.7, 2.8, 2.9 and 2.10 the proof follows.

Case 2: n1(mod8).

Let n=4t+1, t is even. When t=2, the proof follows from Lemma 2.8. We observe that for t4, (4)K4t+1=K4(t2)K9K4(t2)+12(t2),8 Also for t6, (5)K4(t2)+12(t2),8=K4(t4)+12(t2),8K9,8.

From (4) and (5), (6)K4t+1=K4(t2)K9K4(t4)+12(t2),8K9,8,t6.

Assume that the theorem is true for all even k < t. We have to prove for t=k+2. From (6), we can write, K4(k+2)+1=K4kK9K4(k2)+12k,8K9,8.

By induction hypothesis and from Lemmas 2.7, 2.8 and 2.11 the proof follows. ◻

Theorem 2.13. (Main Theorem) For non-negative integers α, β and n8, Kn=αP5βY5 if and only if 4(α+β)=(n2).

Proof. The proof follows from Theorems 2.4 and 2.12. ◻

3. Multi-decomposition of complete bipartite graphs into P5 and Y5

3.1. Necessary conditions

In this section, we derive the necessary conditions for the existence of multi-decomposition of Km,n, (m>2,n2) into paths and Y-trees with 5 vertices.

Lemma 3.1. Let k be even. If K2k,2 has a (P5,Y5) – multi-decomposition for the admissible pair (α,β), then α is even.

Proof. Let V(K2k,2)=V1V2, where |V1|=2k, |V2|=2 and |E(K2k,2)|=4k. P5 has a degree sequence (2,2,2,1,1). While decomposing K2k,2 into P5’s and Y5’s, the two vertices of P5 with degree 2 which are incident with a vertex of degree 1, should be formed using the vertex set V2= {v21,v22}. Y5 has a degree sequence (3,2,1,1,1). Here, the vertex with degree 3 and the vertex with degree 1 which is incident with a vertex of degree 2, should be formed using the vertex set V2. Since each vertex in V2 has degree 2k, after decomposing K2k,2 into α number of P5, each vertex v2i, i=1,2 has degree 2k2α and |E(K2k,2αP5)|=4k4α. Since k is even, it is clear that 2(kα){0(mod4),ifαiseven,2(mod4),ifαisodd. Therefore, partitioning the remaining 4(kα) edges into kα number of Y5 is possible only when α is even. ◻

Lemma 3.2. Let k3 be odd. If K2k,2 has a (P5,Y5) – multi-decomposition for the admissible pair (α,β), then α is odd.

Proof. The proof is same as Lemma 3.1 with the same argument. Since k3 is odd, 2(kα){2(mod4),ifαiseven,0(mod4),ifαisodd. Hence the proof follows. ◻

Theorem 3.3. (Necessary conditions) If Km,n has (P5,Y5){α,β} – decomposition, then mn=4(α+β) with m>2 and n>1 except

  1. m=2k, k even; n=2 and α is odd

  2. m=2k, k3 odd; n=2 and α is even

Proof. The proof follows from edge divisibility condition and by Lemmas 3.1 and 3.2. ◻

3.2. Sufficient conditions

In the following lemmas we prove that the above necessary conditions are also sufficient.

Lemma 3.4. K4,2={2P5,or,2Y5.

Proof. By Theorem 3.3, α+β=2. Hence the admissible pairs (α,β) are (0,2), (1,1) and (2,0). By Theorem 1.2, K4,2 can be decomposed into 2P5 and by Theorem 1.3, K4,2 can be decomposed into 2Y5. Hence there exists a (P5,Y5) – multi-decomposition for the admissible pairs (0,2) and (2,0). By Lemma 3.1, it is clear that there does not exist a (P5,Y5) – multi-decomposition for the admissible pair (1,1). Hence the proof. ◻

Lemma 3.5. The graph K6,2 has (P5,Y5) – multi-decomposition for some of the admissible pairs (α,β) where α is odd.

Proof. The admissible pairs for which the decomposition exists are (α,β) {(3,0), (1,2)}. For (3,0), Theorem 1.2 gives the required decomposition. For (1,2), we have the necessary breakdown is as follows:

P5(v11,v21,v12,v22,v13),Y5(v21,v15,v22_,v14;v11_),Y5(v22,v16,v21_,v14;v13_).

The desired decomposition does not exist for the admissible pairs (2,1) and (0,3) by Lemma 3.2. ◻

Lemma 3.6. Let k be even. If α is even in the admissible pair (α,β), then K2k,2 has a (P5,Y5) – multi-decomposition.

Proof. Since k is even, k=2k1 for k1 N. we write, K2k,2=k1K4,2.

Therefore, by Lemma 3.4, for any even α such that α+β=k, there exists a (P5,Y5) – multi-decomposition for the admissible pairs (α,β) with α, β are even. This completes the proof. ◻

Lemma 3.7. Let k3 be odd. If α is odd, then K2k,2 has (P5,Y5) – multi-decomposition.

Proof. Since k1 is odd, k=2q+1 for q N. we write, K2k,2=(q1)K4,2K6,2.

Therefore, by Lemmas 3.4 and 3.5, for any odd α such that α+β=k, there exists a (P5,Y5) – multi-decomposition for the admissible pairs (α,β) with α is odd and β is even. This completes the proof. ◻

Lemma 3.8. The graph K4,3 admits (P5,Y5){α,β} – decomposition whenever α+β=3.

Proof. Case 1: (3,0).

Theorem 1.2 gives required 3P5’s.

Case 2: (2,1).

P5(v21,v12,v22,v11,v23),P5(v11,v21,v13,v22,v14),Y5(v21,v14,v23_,v13;v12_).

Case 3: (1,2).

P5(v21,v14,v22,v11,v23),Y5(v22,v12,v23_,v13;v14_),Y5(v22,v13,v21_,v12;v11)_.

Case 4: (0,3).

Theorem 1.3 gives the required decomposition. ◻

Lemma 3.9. The graph K4,4 admits (P5,Y5){α,β} – decomposition whenever α+β=4.

Proof. Case 1: α is even i.e.,(α,β) {(4,0), (2,2), (0,4)}.

Since K4,4=2K4,2, Theorems 1.2 and 1.3 give the required decomposition.

Case 2: α is odd.

Subcase 1: (3,1). P5(v11,v22,v14,v23,v13),P5(v21,v14,v24,v12,v22),P5(v12,v23,v11,v24,v13),Y5(v22,v13,v21_,v12;v11_)

Subcase 2: (1,3). P5(v12,v22,v13,v21,v14),Y5(v13,v23,v14_,v24;v22_),Y5(v13,v24,v11_,v23;v22_),Y5(v11,v21,v12_,v24;v23_) ◻

Lemma 3.10. The graphs K4,5 and K4,6 admits (P5,Y5){α,β} – decomposition whenever α+β=5 and α+β=6 respectively.

Proof. We can write K4,5=K4,2K4,3, K4,6=2K4,3. Then the proof follows from Lemmas 3.4 and 3.8. ◻

Lemma 3.11. The graph K6,6 admits (P5,Y5){α,β} – decomposition whenever α+β=9.

Proof. We can write K6,6=K4,6K2,6. Since Km,nKn,m, the proof follows from Lemmas 3.5 and 3.10. ◻

Lemma 3.12. If k,nN, n3, then K4k,n can be decomposed into admissible pairs of P5 and Y5.

Proof. Let n=4q+r for q>0 and r{0,1,2,3}.

If r=0, K4k,n=K4k,4q=kqK4,4.

For r=1, K4k,n=K4k,4q+1=K4k,4(q1)+5=k(q1)K4,4K4,5.

When r=2, K4k,n=K4k,4q+2=K4k,4(q1)+6=k(q1)K4,4K4,6.

When r=3, K4k,n=K4k,4q+3=kqK4,4K4,3.

Then the proof follows from Lemmas 3.8, 3.9, 3.10 and by mathematical induction on k, n◻

Lemma 3.13. If k1,k23 be odd, then K2k1,2k2 can be decomposed into admissible pairs of P5 and Y5.

Proof. Since k11, k21 are odd, k1=2q1+1 and k2=2q2+1 for q1,q2N and we write, K2k1,2k2=(q11)(q21)K4,4(q11)K4,6(q21)K6,4K6,6.

Then the proof follows from Lemmas 3.9, 3.10, 3.11 and by mathematical induction on k1, k2◻

Theorem 3.14. (Sufficient Conditions) If m,n,α and β satisfy the necessary condition given in Theorem 3.3, then Km,n has (P5,Y5){α,β} – decomposition.

Proof. Case 1: m0(mod4) or n0(mod4), w.l.o.g, let m=4k for kN.

Subcase 1.1. n=2.

Lemma 3.6 gives the required decomposition.

Subcase 1.2. n3.

Lemma 3.12 gives the required decomposition.

Case 2: m0(mod2) and n0(mod2), i.e., m=2k1, n=2k2 for k1, k2 N.

Subcase 2.1. When one of them is 2, w.l.o.g, let n=2.

When k1 is even, this falls in Subcase 1.1. If k11 is odd, Lemma 3.7 gives the required decomposition.

Subcase 2.2. m,n>2.

When one of k1 and k2 or both of them are even, then the proof follows from Subcase 1.2. If both of them are odd, Lemma 3.13 gives the required decomposition. ◻

Theorem 3.15. (Main Theorem) There exists (P5,Y5){α,β} – decomposition of Km,n if and only if any one of the following holds:

  1. m=2k,k is even, n=2 and α is even.

  2. m=2k,k3 is odd, n=2 and α is odd.

  3. m=4k and n3.

  4. m=2k1 and n=2k2; where k1,k23 are odd.

Proof. Proof follows from Theorems 3.3 and 3.14. ◻

4. Conclusion

In this paper, it is proved that the necessary and sufficient condition for the existence of the (P5,Y5){α,β} – decomposition of the complete graph Kn (n8) is n0or1(mod8). Also we have obtained the necessary and sufficient conditions for the (P5,Y5){α,β} – decomposition of the complete bipartite graph Km,n (m>2, n2) as mn=4(α+β) whenever

  1. m=2k, k even; n=2 then α is even.

  2. m=2k, k3 odd; n=2 then α is odd.

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